2017/2018 Neco Gce Physics ( Alt to Practical ) Questions/Answers, Solution.

(1ai – 1aiii)
i: 1, 2, 3, 4, 5, 6
X(cm): 10.00, 15.00, 20.00, 25.00, 30.00
Y(cm): 20.00, 17.40, 15.20, 12.60, 10.40
Z(cm): 17.40, 15.20, 13.40, 11.20, 9.40
P= y-z(cm): 2.60, 2.20, 1.80, 1.40, 1.00

(1av)
Slope, S = y2-y1/x2-x1
= 56.7-20/4-1
= 36.7/3
= 12.233
= 12.23

(1avi)

U = 100/s
= 100/12.23 = 8.176
= 8.18

(1avii)

(i) I will avoid error due to parallax while reading the metre rule

(ii) I will ensure the mass is kept dried before weighing

(1bi)
Weight in air = 10/1000
= 0.01kg
Weight in water = 9.75kg
9.75/9.75-0.01
= 9.75/9.74 = 1.00
Density of solid = 1/1000 = 0.001g/cm-³

(1bii)
It is because the molecules of the particles is packed together and no space for air interference while solid pieces of iron has volatile or irregular pattern which allows air interference

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2bi)
I Rainbow
II Wave length

2bii)
M=V/U
object height=8cm
Image height=192cm
M=192/8
M=24cm

2v)
SLOPE​
Slope,s =y2-y1/x2-x1
=56.7-20/4-1
=36.7/3
=12.233
=12.23

2vi)
U = 100/S = 100/12.23
= 8.176
=8.18

2vii)
– I will avoid error due to parallax while reading the meter rule.
-I will ensure the mass is kept dried before weighing

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3a)
Readings​
1 | R(ohms) | R^-1(ohms)| L(cm) | L(cm)
1 | 1.00 | 1.000 | 13.50 | 0.074
2 | 2.00 | 0.500 | 27.50 | 0.036
3 | 3.00 | 0.333 | 41.50 | 0.024
4 | 4.00 | 0.250 | 55.00 | 0.018
5 | 5.00 | 0.200 | 69.00 | 0.014

Note:​ where u see ohms put the ohms sign

(3av)
Slope=Change in R^-1/Change in L^-1
=(0.500-0.200)/(0.036-0.018)
S=0.30/0.018
=16.67cm/n

(3avi)
Rs=100/16.67
Rs=5.99880n/cm
Rs=6.0n/cm

(3avii)
-I must be ensured of accurate readings thrrough my resistance box
-I must be ensured of tight connections throughout my experiments

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