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2019 Lagos Ss2 Mock Mathematics { Obj/Essay } Solutions.

2019 LAGOS SS2 MOCK MATHEMATICS ANSWERS
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Obj:
01-10:
11-20:
21-30:
31-40:
41-50:

Obj Answers Loading……℅..
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PART 1(instructions says, Answer all questions in this part)

(1a) TABULATE: MODULE 7
X| 1| 2| 5| 6|
1| 1| 2| 5| 6|
2| 2| 4| 3| 5|
5| 5| 3| 4| 2|
6| 6| 3| 2| 1|

(1b)
(1*2)*(2*6)
=2(mod 7)*12(mod 7)
=2(mod 7)*5(mod 7)
=10(mod 7)
=3(mod 7)

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(2a)
Sin x=-0.5
Sin–¹(0.5)=-30°

Since sin is negative in only the 3rd and 4th quadrant
x° between 90° and 360° is given as;

x=360°-30°
x=330°
And x=180°+30°
x=210°

Therefore, the values of x are 330° or 210°

(2b)
(x-2)(x-3)=12
x²-3x-2x+6=12
x²-5x+6=12
x²-5x=12-6
x²-5x=6

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(3)
{Click here to view the image}
r=d/2
r=26/2
r=13cm

{Click here to view image}
r²=5² + (x/2)² Pythagoras theorem
13²=5² + (x²/4)
169=25 + x²/4
169 – 25=x²/4
144=x²/4
Cross multiply
144*4=x²
576=x²
==> x²=576
Square root both sides
√x²=√576
x=24cm.

:. x is the length of the cord and it is 24cm

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(4i)
A=x² – y² / x² + xy
From; a² -b²=(a + b) (a – b) {difference of two squares}
A=(x + y) (x – y) / x² + xy
A=(x + y) (x – y) / x(x + y)
A=x – y / x

(4ii)
{Find A if x= -4 and y= -6}
A=x² – y² / x² + xy
A=x – y / x
A= -4 – (-6)/ -4
A= -4 + 6 / -4
A= 2 / -4
A= – 1/2

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(5)
4x+1=5x-y
4x-5y+y=-1
-x+y=-1
Multiply through by -1
x-y=1———————(1)
5x+5=x+7y
5x-x-7y=-5
4x-7y=-5——————(2)
Substitute for x in equation (1)
x-y=1
x=1+y———————(3)
Put equation (3) in (2)
4x-7y=-5
4(1+y) -7y=-5
4+4y-7y=-5
4-3y=-5
-3y=-5-4
-3y=-9
Divide both sides by -3
-3y/-3=-9/-3
y=3
substitute y=3 in equation (3)
x=1+y
x=1+3
x=4
Therefore x,y=(4,3)

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PART B(Answer any five questions from this Part)

(6i)
{Click here to view the image}

(6ii)
{Click here to view the image}
[Meaning of this sign ∅ is tita, take note]
∅=50°+60°
∅=110°
x²=b²+c²–2bc cosA (cosine rule)
x²=2²+5²–2(2*5) cos 110°
x²=4+25–2(10) * cos 110°
x²=29–20*–0.3420
x²=29+6.84
x²=35.84
x=√35.84
x=5.9867
x≈6.0km to 1dp

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(7a)
A(-2,7) B(2,-3)
y=mx+c
m=y2–y1/x2–x1
y2=7
y1=–3
x2=–2
x1=2
m=7–(–3)/–2–2
m=7+3/–4
m=10/–4
m=–5/2 or –2½

To find c
y2=mx2+c
7=(–5/2)(–2)+c
7=10/2+c
7=5+c
c=7–5
c=2

:. y=–5/2x+2
y=2–5x/2

(7b)

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(8a)
x |–2|–1|0|1|2|3|4|
y | a | b |6|c |4|d|e|
{Find, a, b, c, d, e}
y=6+x–x²

(a)
when x=2, y=?
y=6+(–2)–(–2)²
y=6+(–2)–4
y=6–2–4
y=0//

(b)
when x=–1, y=?
y=6+(–1)–(–1)²
y=6+(–1)–(1)
y=6–1–1
y=4//

(c)
when x=1, y=?
y=6+1–(1)²
y=7–1
y=6//

(d)
when x=3, y=?
y=6+3–(3)²
y=9–9
y=0//

(e)
When x=4, y=?
y=6+4–(4)²
y=10–16
y=–6

therefore the complete table will be:
x |–2|–1|0|1|2|3| 4|
y | 0 | 4l6|6|4|0|–6|

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Updated: September 22, 2019 — 8:34 pm

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