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WAEC GCE 2019: Verified Mathematics { Essay & Obj } Questions And Solutions.

MATHS OBJ:
1-10: BBDCCBCBBA
11-20: BCBDCDBDDB
21-30: BCBDBBAACA
31-40: AABBDABCCB
41-50: BBBDBCBCDB

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(1a)
Tabulate
X|2|3|4|5|7|
2|4|6|2|6|
3|6|1|7|5|
5|2|7|1|3|
7|6|5|3|1|

(1bi)
n=7,i;e 3 (*)7=5

(1bii)
n(*)n=1, n=3

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(2a)
Given; slant height l = 18.7cm
Diameter, d = 24cm
π = 22/7
But, Curved surface area of cone = πrl
=π(d/2)l
= 22/7 × 24/2 × 18.7
=9873.6/14 = 705cm²

(2b)
128^x × 2/16^(1-x) = 8⅔x
= 2^7x × 2/2^4(1-x) = 2³(⅔x)
= 2^7x + 1/2^4(1-x) = 2^2x
Cross multiply
2^4(1 – x) + 2x = 2^7x + 1
4(1 – x) + 2x = 7x + 1
4 – 4x + 2x = 7x + 1
4 – 2x = 7x + 1
9x = 3
X = 3/9 = 1/3

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(3a)
3√3/2 – 4√2/3 – √24
=3√3/2 – 4√2/√3 -√6*4
=(3√3/√2 × √2/√2) – (4√2/√3 × √3/√3) – 2√6
=3√6/2 – 4√6/3 – 2√6
=(3/2 – 4/3 – 2)√6
=(9 – 8 – 12)√6
= -11/6√6

(3bi) prob(only one passes) = m passes and N fails or M fails and N passes
Prob (M passes) = 2/3; prob(M fails) = 1 – 2/3 = 1/3
Prob(N passes) = 4/5; prob(N fails) = 1 – 4/5 = 1/5
Prob(only one passes) = (2/3 × 1/5) + (1/3 × 4/5)
= 2/15 + 4/15
= 6/15
= 2/15

(3bii)
prob(at least one passes) = prob(only one passes) + prob(both parties)
= 2/5 + (2/3 × 4/5)
= 2/5 + 8/15
= 6/15 + 8/15
= 14/15

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(4a)
17²=X²+15²
17²=X²+225
289-225=X²
64=X²
C=√64=8
Tanθ=18/15
Tanθ/1+2tanθ=18/15/1+2(8/15)=8/15/1+16/15
=8/15÷31/15=8/15*15/31=8/31

(4b)
Log^10/Log^64=½
Log10^10=Log10^64^½
y=√64=±8

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(5a)
Obtuse Reflex
11
8th –> 20
a + (n -1)d = 11
a + (5ˉ¹)d = 11
a + 4d = 11 –> (i)
a + 7d = 20 –> )ii)
a + 7d – a – 4d = 20 – 11
7d – 4d = 9
3d = 9
D = 9/3 = 3
D = 3
From eqn (i)
a + 4d = 11
a + 4 x 3 = 11
a + 12 = 11
a = 11 – 12
a = 1

(8ai)
Tn = a + (m-1)d
T₂ = -1 (12 – 1) 3
= -1 + 11 x 3
= -1 + 33
T12 = 32

(8aii)
Sn = n/2 [2a + (n – 1)d]
= 12/2 [ 2 x (1) + 11 x 3]
= 6 [ -2 + 33)
= 6 (31)
= 186

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(9i) DRAW THE DIAGRAM

n (U) = 110
n (P) = 25
n (B) = 45
n (M) = 48
n (Pnm) = 10
n (Bnm) = 8
n (pnBnm) = 5

(9ii) for biology = 45 = 36

(9iii)
x + 14 + 1 + 5 + 5 + 36 + 3 + 35 = 110
x + 25 + 36 + 38 = 110
x = 110 – 99
x = 11

(9b)
15 = 22 + 18 + 2 x 1 + 10 +20/5
15 x 5 = 40 + 2x + 31
45 = 71 + 2x
45 – 71 + 2x
2x/2 = -26/2
X = 13
22, 18, 2x + 1, 10 , 20
For 2x (-B) +1 = -26 +1 = -25
22, 18, -25, 10, 20
-25, 10, 18, 20, 22
The media is 18

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(12)
Draw the diagram
x² = 20² + 8² – 2x 20 x 8 x Cos 50º
x² = 400 + 64 – 320 x 0.6427
x² = 464 – 205.7
√x² = √258.3
x = 16.1
x = 16km

(12ai) TJ = 16km

(12aii) sinØ/20 = sin50/16
sinØ = 20 x sin 50/16
sinØ 0.9576
Ø = sinˉ¹ 0.9576 = 73.3º
The bearing 90 -73.3 = 16.7º

(12b)
Draw the diagram
y = √12² + 5²
y = √144 + 25
y = √169 = 13
tan Ø = 5/12 = (0.04167)
Ø = tanˉ¹ (0.4167) = 22.6º
Sin Ø = 5/6 + x
Sin 22.6º = 5/6 + x
(0.3843) (6 + x) = 5
2.3058 + 0.3843x = 5
0.3843x = 5-2.3058
0.3843x/0.3843 = 2.6942/0.3943
X = 7.01
X ≈ 7

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(13a)
Draw the diagram

(i) Extend DO to touch AB at M
AOD + AOM = 180°(

Updated: September 8, 2019 — 8:20 am

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